# wavelength of proton

## wavelength of proton

Read the question carefully, and you should see it says proton... That is, a mass-ive particle with rest mass m_p = 1.673 xx 10^(-27) "kg". Problem #2: What is the wavelength in meters of a proton traveling at 255,000,000 m/s (which is 85% of the speed of light)? The waves which travel in the form of oscillating electric and magnetic waves are called electromagnetic waves. This means that if we were to solve for an object’s speed in terms of its kinetic energy, then that speed is equal to the square root of two times its overall kinetic energy divided by . Our kinetic energy is in units of electron volts, but we’d like to convert this to units of joules to be consistent with the rest of our values. Since energy is same and mass of proton is more , it's momentum will be more . (Assume the mass of the proton to be 1.673 x 10¯ 27 kg.) Objects with a rest mass follow the de Broglie relation: lambda = h/(mv) = h/p and have kinetic energy given by K = 1/2 mv^2 = p^2/(2m), where: h = 6.626 xx 10^(-34) "J"cdot"s" is Planck's constant. Comparing with the proton above, the wavelength for the proton is about #10# times the wavelength for this #alpha# particle at this velocity, which again makes physical sense. Wavelength of photon is depends on the source from which it emitted.. Photon of the X-ray spectra has the different wavelength than the photon of the gamma ray spectra.. Then the kinetic energy of the electron is? Experts are waiting 24/7 to provide step-by-step solutions in as fast as 30 minutes!*. Find answers to questions asked by student like you, Calculate the de Broglie wavelength of a proton moving at 2.42 ✕ 108 m/s. c) Using P = √(2Km) . a = (2.00i + 5.00j) m/s². F=-kx (c) Equal to the kinetic energy of the proton, (d) Greater than the kinetic energy of the proton. To start, let’s recall the mathematical relationship for the de Broglie wavelength of a particle. Question 11: The operation of the electron microscope depends on the: The wave nature of the electron particles is utilized in the electron microscope. We want to solve for the de Broglie wavelength of this proton; we’ll call that . The wavelength of an electron moving 5.31 x 106 m/sec is 1.37 x 10-10 m or 1.37 Å. It can also be determined by ta... Q: Express 200C and -50C on the Kelvin scale. A: conversion between C and kelvin scale is  m/sec. Median response time is 34 minutes and may be longer for new subjects. by x(t)=Asin(wt), where A is the a... A: For a simple harmonic oscillator the force acting is given by , Then the kinetic energy of the electron is? The photon’s energy depends only on the frequency of the photon. We want to solve for the de Broglie wavelength of this proton; we’ll call that . de Broglie wavelength λ of a particle = h /P a) since mass of proton is more than electron and speed is same , momentum of proton is more . The angular speed is given by, Question. The de Broglie wavelength is inversely proportional to momentum. The waves associated with microscopic particles when they are in motion are called matter waves. k = C+273. (Mp 938.27 MeV/c2 -1.6726 1027 kg, c 3 108 m/s) 6.8 Hint: Look again at the de Broglie wavelength formula λ= h/p Remember that the momentum is p=mv Please report your results in 1015 m Question 6: Which of the following is associated with an electron microscope? (c) greater than the kinetic energy of the particle. proton Compton wavelength †: Numerical value: 1.321 409 855 39 x 10-15 m : Standard uncertainty: 0.000 000 000 40 x 10-15 m : Relative standard uncertainty: 3.1 x 10-10: Concise form The electron and the proton have the same de Broglie wavelength, which means their momenta are the same. The wavelength of a 2 eV photon is given by: l = h c / E ph = 6.625 x 10-34 x 3 x 10 8 /(1.6 x 10-19 x 2) = 621 nm. This value is also known as 20 femtometers. 9: An electron and a proton have the same de Broglie wavelength. What is the wavelength (in 10-15 m) of a proton traveling at 15.6% of the speed of light? Q: A 3.00-kg object undergoes an acceleration given by Now that we have values for ℎ, , and KE, we’re ready to plug into this equation. A: (a) Nagwa is an educational technology startup aiming to help teachers teach and students learn. ωt... Q: The position of a simple harmonic oscillator with mass m is given Using that value under our square root sign for the energy, when we compute , we find that it’s equal to 20 times 10 to the negative 15th meters. Nagwa uses cookies to ensure you get the best experience on our website. And in general, the kinetic energy of an object, KE, is equal to one half the mass of the object times its speed squared. What is the de Broglie wavelength of a proton whose kinetic energy is 2.0 megaelectron volts? *Response times vary by subject and question complexity. where the photon energy was multiplied with the electronic charge to convert the energy in Joule rather than electron Volt. When we recall that momentum is equal to an object’s mass times its velocity, , that means we can apply the de Broglie wavelength equation to our scenario by writing that the wavelength of the proton equals Planck’s constant divided by the proton’s mass times its speed. For an electron with KE = 1 eV and rest mass energy 0.511 MeV, the associated DeBroglie wavelength is 1.23 nm, about a thousand times smaller than a 1 eV photon.

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